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4.5w^2+5.6w=0
a = 4.5; b = 5.6; c = 0;
Δ = b2-4ac
Δ = 5.62-4·4.5·0
Δ = 31.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{31.36}}{2*4.5}=\frac{-5.6-\sqrt{31.36}}{9} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{31.36}}{2*4.5}=\frac{-5.6+\sqrt{31.36}}{9} $
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